Optimal. Leaf size=100 \[ \frac {a \left (2 a^2+9 b^2\right ) \sin (c+d x)}{3 d}+\frac {1}{2} b x \left (3 a^2+2 b^2\right )+\frac {7 a^2 b \sin (c+d x) \cos (c+d x)}{6 d}+\frac {a^2 \sin (c+d x) \cos ^2(c+d x) (a+b \sec (c+d x))}{3 d} \]
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Rubi [A] time = 0.15, antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {3841, 4047, 2637, 4045, 8} \[ \frac {a \left (2 a^2+9 b^2\right ) \sin (c+d x)}{3 d}+\frac {1}{2} b x \left (3 a^2+2 b^2\right )+\frac {7 a^2 b \sin (c+d x) \cos (c+d x)}{6 d}+\frac {a^2 \sin (c+d x) \cos ^2(c+d x) (a+b \sec (c+d x))}{3 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 2637
Rule 3841
Rule 4045
Rule 4047
Rubi steps
\begin {align*} \int \cos ^3(c+d x) (a+b \sec (c+d x))^3 \, dx &=\frac {a^2 \cos ^2(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{3 d}+\frac {1}{3} \int \cos ^2(c+d x) \left (7 a^2 b+a \left (2 a^2+9 b^2\right ) \sec (c+d x)+b \left (a^2+3 b^2\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {a^2 \cos ^2(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{3 d}+\frac {1}{3} \int \cos ^2(c+d x) \left (7 a^2 b+b \left (a^2+3 b^2\right ) \sec ^2(c+d x)\right ) \, dx+\frac {1}{3} \left (a \left (2 a^2+9 b^2\right )\right ) \int \cos (c+d x) \, dx\\ &=\frac {a \left (2 a^2+9 b^2\right ) \sin (c+d x)}{3 d}+\frac {7 a^2 b \cos (c+d x) \sin (c+d x)}{6 d}+\frac {a^2 \cos ^2(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{3 d}+\frac {1}{2} \left (b \left (3 a^2+2 b^2\right )\right ) \int 1 \, dx\\ &=\frac {1}{2} b \left (3 a^2+2 b^2\right ) x+\frac {a \left (2 a^2+9 b^2\right ) \sin (c+d x)}{3 d}+\frac {7 a^2 b \cos (c+d x) \sin (c+d x)}{6 d}+\frac {a^2 \cos ^2(c+d x) (a+b \sec (c+d x)) \sin (c+d x)}{3 d}\\ \end {align*}
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Mathematica [A] time = 0.12, size = 80, normalized size = 0.80 \[ \frac {a^3 \sin (3 (c+d x))+9 a \left (a^2+4 b^2\right ) \sin (c+d x)+9 a^2 b \sin (2 (c+d x))+18 a^2 b c+18 a^2 b d x+12 b^3 c+12 b^3 d x}{12 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.46, size = 66, normalized size = 0.66 \[ \frac {3 \, {\left (3 \, a^{2} b + 2 \, b^{3}\right )} d x + {\left (2 \, a^{3} \cos \left (d x + c\right )^{2} + 9 \, a^{2} b \cos \left (d x + c\right ) + 4 \, a^{3} + 18 \, a b^{2}\right )} \sin \left (d x + c\right )}{6 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 170, normalized size = 1.70 \[ \frac {3 \, {\left (3 \, a^{2} b + 2 \, b^{3}\right )} {\left (d x + c\right )} + \frac {2 \, {\left (6 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 9 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 18 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 4 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 6 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 9 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 18 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3}}}{6 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.76, size = 76, normalized size = 0.76 \[ \frac {\frac {a^{3} \left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{3}+3 a^{2} b \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+3 b^{2} a \sin \left (d x +c \right )+b^{3} \left (d x +c \right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.34, size = 73, normalized size = 0.73 \[ -\frac {4 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} a^{3} - 9 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} a^{2} b - 12 \, {\left (d x + c\right )} b^{3} - 36 \, a b^{2} \sin \left (d x + c\right )}{12 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.86, size = 77, normalized size = 0.77 \[ b^3\,x+\frac {3\,a^3\,\sin \left (c+d\,x\right )}{4\,d}+\frac {a^3\,\sin \left (3\,c+3\,d\,x\right )}{12\,d}+\frac {3\,a^2\,b\,x}{2}+\frac {3\,a^2\,b\,\sin \left (2\,c+2\,d\,x\right )}{4\,d}+\frac {3\,a\,b^2\,\sin \left (c+d\,x\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \sec {\left (c + d x \right )}\right )^{3} \cos ^{3}{\left (c + d x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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